Human Anatomy & Physiology (Human Body Systems)
Unit 4: Unit 4: Human Systems & Patient CareHBS 4.1Human Body Systems: renal & digestive

Interpret a urinalysis result

Read a urinalysis (or protein electrophoresis) value against its normal range to decide whether a result is healthy or signals a problem.

Builds on (2 levels back)inferred · high confidence
  • Comparing a value to a normal range: A urinalysis is read by checking a measured value against a stated normal range, so students must first be able to compare a number to a range.
  • What a healthy nephron sends to urine: Healthy urine has no glucose and no large protein; knowing the normal output is needed before judging an abnormal result.

Prerequisites are inferred: pending teacher review.

Re-learn the skill with worked practice and clear examples.

A urinalysis reports what is dissolved in urine. Read each value against its normal range; healthy urine normally shows no glucose and no large protein.

Step 1: Know the normal output
A healthy nephron reabsorbs all glucose and holds back large proteins, so healthy urine normally contains no glucose and no large protein.
Step 2: Read each row
For each substance, compare the patient's value to the normal range printed beside it. A value inside the range is normal for that row.
Step 3: Flag the outliers
A value outside its normal range is the one to investigate: but the table only shows the numbers; the verdict comes from your comparison, not from the report.
Practice

Use the table. For glucose, how does the patient's value compare to its normal range?

Reviewed
SubstancePatient valueNormal range
Glucose250 mg/dL0 mg/dL (none)
Protein (large)0 mg/dL0 mg/dL (none)
pH6.04.5 to 8.0
A urinalysis table with three rows (glucose, large protein, pH), each listing a patient value and a normal range for the student to compare.
  1. A.The glucose value is inside its normal range
  2. B.The glucose value is above its normal range
  3. C.The glucose value is below its normal range
  4. D.The table does not list a normal range for glucose
Show the worked solution ▾

Answer: B. The glucose value is above its normal range

  1. Step 1: Read the glucose row: The patient value is 250 mg/dL and the normal range is 0 mg/dL (none).
  2. Step 2: Compare: 250 is far above 0, so the glucose value is above its normal range.

Why it's right: The normal glucose value is 0 (none), and 250 mg/dL is well above that, so glucose is above its normal range.

Why the others miss:
  • A: 250 is not within a normal range of 0.
  • C: 250 is greater than 0, not below it.
  • D: The table lists 0 mg/dL (none) as the normal range for glucose.

Aligned to HBS: interpret urinalysis · reading level ~grade 9

Where you'd see this
  • A clinic reads a urinalysis row by row, comparing each value to its normal range before deciding what the results mean together.
Video library
Watch: Interpret a urinalysis result
Urinalysis | Urine Dipstick Test | OSCE Guide | UKMLA | CPSA | PLAB 2
Geeky Medics · ~5 min
Guided notes

Fill these in as you work through the lesson.

Big idea: A urinalysis is a test that reports what is dissolved in urine; you read each value against its normal range to decide whether it is healthy.
Key terms: write the meaning
  • Urinalysis (a test of what is in urine):  
  • Normal range (the healthy band of values):  
  • Glucose (should not appear in healthy urine):  
  • Protein (large ones should not appear in healthy urine):  
The rule

Healthy urine should contain   glucose and   large protein, so a result is compared to its   to decide if it is a problem.

Check yourself
  1. Why do you need a normal range printed beside a urinalysis value to interpret it? 
  2. Name one substance that should read 'none' in healthy urine. 
  3. If a value falls inside its normal range, what does that suggest about that part of the test? 
Work one example

A urinalysis report lists glucose, protein, and pH, each with a normal range. Pick one value, compare it to its normal range, and state whether that single value is normal or abnormal and how you decided.